Creating an Image matrix (5x10) from a 5x100 matrix

clc 
clear all
I = 1;
b0 = I; ep0 = 0; c0=0; a10=0;



tMax=30; dt=0.1;
timeVector = 0:dt:tMax; nIterations = length(timeVector); 

conc_blood = [];
conc_endo = [];
conc_liver = [];

%euler

b(1) = b0;
ep(1)= ep0;
c(1) = c0;

for i = 1:100
    
    
    ra12_1(i) = rand; ia12_1 = 0.3;
    if ra12_1(i)>=ia12_1
        a12_1(i)=0.5;
    else 
        a12_1(i) = 0;
    end 
    
        ra12_2(i) = rand; ia12_2 = 0.3;
    if ra12_2(i)>=ia12_2
        a12_2(i)=0.5;
    else 
        a12_2(i) = 0;
    end 
    
    
    ra23_1(i) = rand; ia23_1=0.5;
    if ra23_1(i) >= ia23_1
        a23_1(i) = ia23_1;
    else 
        a23_1(i) = 0;
    end 
    
    
        ra23_2(i) = rand; ia23_2=0.5;
    if ra23_2(i) >= ia23_2
        a23_2(i) = ia23_2;
    else 
        a23_2(i) = 0;
    end 
    
    ra21_1(i) = rand; ia21_1=0.5;
    if ra21_1(i) >= ia21_1
        a21_1(i) = ia21_1;
    else 
        a21_1(i) = 0;
    end
    
    
    ra21_2(i) = rand; ia21_2=0.5;
    if ra21_2(i) >= ia21_2
        a21_2(i) = ia21_2;
    else 
        a21_2(i) = 0;
    end 
    
    
    c1(1) = c0;
    ep1(1) = ep0;   
    b(1) = b0;
    ep2(1)= ep0;
    c2(1) = c0;
    
    
    c1(i+1)=c1(i)+dt*liver1(timeVector(i),a23_1(i),ep1(i));
    ep1(i+1)=ep1(i)+dt*endo1(timeVector(i),a12_1(i),ep1(i),a21_1(i),b(i),a23_1(i));
    b(i+1)=b(i)+dt*blood(timeVector(i), a10, a12_1(i), a12_2(i), b(i), a21_1(i), a21_2(i), ep1(i), ep2(i));
    ep2(i+1)=ep2(i)+dt*endo2(timeVector(i),a12_2(i),ep2(i),a21_2(i),b(i),a23_2(i));
    c2(i+1)=c2(i)+dt*liver2(timeVector(i),a23_2(i),ep2(i))
    
A = [c1; ep1; b; ep2; c2]; 
imagesc(A)
colormap winter
colorbar

end 

Hello everyone!

I am trying to create an image matrix from the code above. I have created a 5x100 image matrix which contains all of the values recieved. However, intead of receiving this monstrosity of an image I would like a 5x10 matrix to get updated with the values as the code is running. Basically I would like to push a 5x10 matrix through the bigger matrix and (keeping the size 5x10) running along the 'gradient' of the bigger matrix. This I would like to be done with a .1 second pause for every update and display those with a colormap (which I can do later so this is not crucial atm). Does anyone know how to do this or are able to help, every thought is appreciated.

Thanks in beforehand!

Answer 1

[KALYAN ACHARJYA]

"I have created a 5x100 image matrix which contains all of the values recieved. However, intead of receiving this monstrosity of an image I would like a 5x10 matrix to get updated with the values as the code is running. Basically I would like to push a 5x10 matrix through the bigger matrix"

I have answered this based on the description in your question, hope I understood it correctly. eg.

data_test=[];
for c=1:10
    data=rand(5,10); %Random data 5x10
    data_test=[data_test,data]; % Horizantal concatenation with previous data
    imagesc(data_test)
    %colormap winter
    colorbar
    pause(1);
    clf;
end 

"keeping the size 5x10"

For the resultant matrix?

[William Larsson]

Thank you for your answer! However, it was not quite what i was looking for. I do not want the matrix to grow bigger than 5x10. The updating part worked, but it looks like it did before.

I will try to rephrase myself: For example, at the 50th loop I want the last column to represent the 50th loop while the second last represents the 49th and the third last represents the 48th etc. Thereafter, at the 51th loop the last column will be represented by those values and the second last will represent the 50th loop etc. Therefore the matrix will always stay the size 5x10 and the first column will for every iteration be replaced by a new column at the end of the matrix.

Thanks, once again, in beforehand.

Answer 2

[Image Analyst]

Why is it a monstrosity? 5x100 is still very very small (much smaller than a typical digital image for example).

I didn't delve into your question in detail but maybe rem() or mod() is what you want. With that you can reset the columns beyond 5 to the 1-5 range.