if the coding is correct to find the euclidean distance

x=double(imread('result.png'));

[pc, score,latent,tsquare] = princomp(x);

y=double(imread('result1.png'));

[pc1,score1,latent1,tsquare1] = princomp(y);

img=latent;

img2=latent1;

dist = sqrt(sum((img - img2) .^ 2));

ITS A CORRECT CODING SIR

Answer 1

[Walter Roberson]

Maybe. It is not obvious to me that taking the euclidean distance of the latent is meaningful, though. Also I see no inherent reason why the vectors would be the same length unless the images happened to be the same size.

Answer 2

[Jan]

Please note that uppercase characters means shouting in a forum.

It is hard to guess, if the coding is correct, when you do not explain, what the function should do. Perhaps you want a single number as output:

dist = sqrt(sum((img(:) - img2(:)) .^ 2))

[Walter Roberson]

princomp is documented as returning a vector for the "latent" output parameter, so it should not be necessary to use (:)