how to convert a 16-bit or 64-bit signed floting point to binary
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masters~ now I'm facing a problem that i have to convert some signed floating point numbers to binary, like -4.182068393394077e-04, or 1.3489.
do anybody have some idea or advices?
thanks
5 Comments
Walter Roberson
on 28 Mar 2013
I have never encountered an unsigned floating point representation. I have encountered unsigned fixed point representations.
The closest you could get to -4.4367e-04 with a signed floating point representation would be to use a scheme with 1 sign bit, 5 exponent bits, 1 "hidden bit", and 10 bits of mantissa. That would allow you to express -(836/1024 + 1) / 2^12, or approximately -4.4346E-04. Notice this only gives you a few decimal places.
5 digits of accuracy requires 16 or 17 bits and the bits for the exponent. 1 sign bit, 5 bits of exponent, 1 hidden bit, 15 bits of mantissa = 21 bits of representation.
Answers (2)
Walter Roberson
on 28 Mar 2013
dec2bin(typecast(TheNumber, 'uint16'), 16) - '0'
16 Comments
Walter Roberson
on 31 Mar 2013
You need binary for the channel encoder. That is
dec2bin(typecast(TheNumber, 'uint16'), 16) - '0'
You can reshape() that to vector form. Just be sure to reshape() it back before using bin2dec() to convert the binary to numeric form.
Jan
on 28 Mar 2013
What exactly is a "binary stream"? It could be a vector of doubles, which contains only ones and zeros. Of a vector of type LOGICAL, or UINT8. Or remember, that all numbers are stored in binary format on a computer, so perhaps this is enough already:
x = pi;
x_bin = typecast(x, 'uint8')
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