Out of memory. The likely cause is an infinite recursion within the program.

% Function for speed

function fv = project_1 (v)
v = [2 3]; % Speed values

g = 9.81; % Gravity
d = .05; % Distance to Mixing System Output
ki = 2.4; % Flow Obstruction Factor in the pipe
D = .0254; % Hose diameter
pe = 746; % Electrical power of the pump
L = 2.2; % Length
ipsilon = .00000101; % Kinematic Viscosity
ro = 997; % Water Density
epsilon = .00001; % Roughness

Re = (v * D)/ ipsilon; % Reynolds Number

f = 1.325./ (log(epsilon /(3.7 * D) + 5.74./(Re.^.9 )).^ 2; % Coefficient of friction
hf = (L * f.*v.^2) / (2 * g * D) + (ki * v.^2 / (2 * g)); % Friction loss

A = 3.141592 * (D^2 / 4); % Cross sectional area
Q = v.* A; % Pipe flow

hb = w./ (Q * ro * g); % Energy gain per pump

fv = ((v.^2) / (2 * g)) + d + hf - hb; % Speed function

% Secant method

i = 2;
err = .00005;

while abs(fv(i)) > err
    v(i+1) = v(i)-(fv(i)*(v(i)-v(i-1)))/(fv(i)-fv(i-1))
    i=i+1;

    fv(i) = project_1 (v);
    if i > 100
        break
    end
end

I'm trying to apply the secant method to the function defined in fv, but I keep getting the out of memory message.

Out of memory. The likely cause is an infinite recursion within the program.

Error in project_1 (line 37)

fv(i) = project_1 (v);

Answer 1

[Cris LaPierre]

Like the error message is saying, your problem is infinite recursion. Your function name is the same as the function you define in line 37. This means the function keeps calling itself endlessly.

If you are supposed to solve this assignment using recursion, you will need to correct your stopping criteria. If not, then you should modify your approach so that your function does not call itself.

[Ramon Cruz]

Thank you very much, I modified the approach of the function.