How can I fix "Index in position 2 exceeds array bounds" in for loop/ if statements?

W=cell(p,1);
for j=1:(p-1);
w=A(index(j):index(j+1)-2);
W{j}=w;
end
W2=cell(p,1);
for j=1:(p-1);
w2=A(index(j):index(j+1)-2);
W2{j}=w2;
end
Z=cell(p,1);
for ii=1:p
P1=W{ii,1};
Z{ii,1}=P1(3:3:end);
end
for ii=1:p
P2=Z{ii,1};
if P2(end,1)>0
W2(ii,1)={[]};
end
end
I am getting the error "Index in position 2 exceeds array bounds" on the line if P2(end,1)>0
The W2 matrix looks how I want it to look I just dont know how to stop it from producing an error.

4 Comments

try debug mode
dbstop if error
and figure out whether everything has the sizes you expect. It looks like P2 is empty, but it's not obvious where that happened
Specifically, it would be useful to know the following at the time of the error:
  • the value of ii
  • the size of P2 (my guess is that it is an empty array)
  • the size of W{ii,1}
Extra question: do you use Z for anything later, or is it purely a temporary variable in this chunk?
at the time of error
ii=10,000 (final p value)
P2 is an empty array
W2 is a 10000x1 cell matrix
Currently it is a temporary variable but eventually I will use Z later! Thank you so much for your help!

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 Accepted Answer

Okay, I believe this code is equivalent to what you have, cleaner and without the error
% pre-allocate with cell arrays of []
W=cell(p,1);
W2=cell(p,1);
Z=cell(p,1);
for ii=1:p
% for all but the last index,
% load in part of A
if ii<p
P1=A(index(ii):(index(ii+1)-2));
% for the last one, not loading anything leaves it empty
% but, we want P1 defined
else
P1=[];
end
W{ii}=P1;
% be explicit about copying W
% there may also be internal Matlab tricks that save some memory with this way
W2(ii)=W(ii);
Z{ii}=P1(3:3:end);
if ~isempty(P1) && Z{ii}(end)>0
W2(ii)={[]};
end
end
A few tricks:
  • instead of separate for loops, combine into one
  • in the last, extra iteration for W1/W2, explicitly leave the cell empty (you may want something else here)
  • avoid packing and unpacking the same cell data
  • you can index into a cell of Z, avoiding the P2 temporary variable
  • isempty check avoids the original error. In this case, the cell will already be empty, anyway

1 Comment

That works great! Thank you! I guess the last value/index in the for loop was causing the problem

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