find the minimum value of x that corresponds to maximum value of theta
3 views (last 30 days)
Show older comments
Hello , I have :
x=30:0.5:300;
h=180;
hypot=sqrt(x.^2+h.^2);
phi=asind(h./hypot);
theta=90-phi;
Now , I want to find the minimum value of x that corresponds to maximum value of theta. How can I do this?
Thanks!
2 Comments
Sean de Wolski
on 13 Feb 2013
FYI, hypot() is a builtin function that does what you have above. So be careful not to overwrite it (and I recommend using it!)
x = 1:10;
y = 3
myHypot = hypot(x,y)
Accepted Answer
Azzi Abdelmalek
on 13 Feb 2013
Edited: Azzi Abdelmalek
on 13 Feb 2013
[~,idx]=max(theta)
out=x(idx)
3 Comments
Azzi Abdelmalek
on 13 Feb 2013
How it works: Example
x=[1 2 3 4 5 6]
y=[10 20 1 21 15 2]
The maximum value of y is 21, it corresponds to index 4, which correspond in x to x(4)
[max_value,idx]=max(y)
out=x(idx)
More Answers (0)
See Also
Categories
Find more on Statistics and Machine Learning Toolbox in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!