How to avoid the rounding off of data ?

I am trying to perform the following divison operation.

l = 2.093750000000000e+09;
l/10^9

It was giving the output as:

ans =

    2.0938

But i need the output as 2.09375 only. How an i achieve it ? I want to use it in further calculations as 2.09375 only. Is there any way to achieve this ?

l = 2.187500000000000e+09;
l/10^9

This was giving desired output in this case.

ans =

    2.1875

If anybody knows how to solve this, please share your thoughts.

Answer 1

[Arthur Roué]

There is no problem here, the default display format is set to short. Try :

format long
l = 2.093750000000000e+09;;
l/10^9

ans =
   2.093750000000000

You can also access to the variable with the variable inspector : just double click on your variable in the workspace explorer.

[Mahesh Babu Dhanekula]

I want this value n = l/10^9 in further calculations.

Will the value stored in "n" is 2.09375 ?

[Mahesh Babu Dhanekula]

It again become 2.0938 even after using format long on top of the code

[Steven Lord]

That's not what I'm seeing:

>> format
>> l = 2.093750000000000e+09;
>> x = l/10^9
x =
    2.0938

>> format long
>> x
x =
   2.093750000000000

>> format longg
>> x
x =
                   2.09375

Or is this related to your other question? The format function does NOT control how a number is converted into a string using string (either explicitly or implicitly by concatenating it with a string array using +.) For that you will need to use something that allows you to explicitly control the way the number is written as text like fprintf or num2str.

[Mahesh Babu Dhanekula]

Thanks for reading my 2 questions. This is exactly what i needed steven.

I have a number 2.093750000000000e+09, and I want to to covert this into 2.09375Hz. So how can i do this ?

If there is any way, please let me know steven

[Steven Lord]

Use fprintf or num2str to create a string or char vector with the desired format then concatenate it with the string "Hz" using +.