# comparing table values using isequal

5 views (last 30 days)
Jakub Steiner on 15 Sep 2020
Commented: Cris LaPierre on 15 Sep 2020
Hi,
I have a table M. The second column contains either the letter 's' or letter 'f'.
I would like to put all the rows with the letter 'f' in the second column into a new table A with the following code
j=1;
TF = isequal ("M(i,2)",'f')
if TF == 1
A(j,:)= M(i,:);
j = j+1;
else
end
end
Unfortunatelly, the isequal function return only zeros. Any idea why? In there syntax error that I'm not aware of?
Testing in a command window:
>> isequal ("M(180,2)",'f')
ans =
logical
0
>> M(180,2)
ans =
table
Var2
_____
{'f'}
Thanks a lot for any answers

Cris LaPierre on 15 Sep 2020
Edited: Cris LaPierre on 15 Sep 2020
This can be done much simpler. Try something like this.
A = M(M{:,2}=="f",:);

Jakub Steiner on 15 Sep 2020
Nice! Works as well and without my clumsy cycles.
Thanks a lot!
Cris LaPierre on 15 Sep 2020
This can be made even simpler by using the variable name:
A = M(M.Var2=="f",:);

Fangjun Jiang on 15 Sep 2020
Edited: Fangjun Jiang on 15 Sep 2020
try TF = isequal (M.Var2{i},'f')

#### 1 Comment

Jakub Steiner on 15 Sep 2020
Works! Thank you a lot

BOB MATHEW SYJI on 15 Sep 2020
TF = isequal ("M(i,2)",'f')
try,
TF = strcmp (M.2nd_variable,'f')

R2020a

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