how to plot curve in matlab
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Hi. How can i plot below equation?
thank you very much
f=(31*f^6)/49000000000 - (667*f^2)/39200 - (657*f^4)/98000000 - (375*cos(qa))/28 - (f^2*cos(qa))/400 + (3*f^4*cos(qa))/7000000 + 375/28;
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David Hill
on 5 Sep 2020
For each qa there potentailly could be six real solutions for f. How do you want to plot that? You could plot the equation's value for different values of qa. For example:
qa=pi/4;%change qa to desired values.
y=@(f)(31*f.^6)/49000000000 - (667*f.^2)/39200 - (657*f.^4)/98000000 - (375*cos(qa))/28 - (f.^2*cos(qa))/400 + (3*f.^4*cos(qa))/7000000 + 375/28;
f=-115:.01:115;
plot(f,y(f));
Answers (1)
KSSV
on 6 Sep 2020
Edited: KSSV
on 6 Sep 2020
Are you looking for something like this?
qa = linspace(-pi,+pi,200) ; % give your ranges
f= linspace(-115,115,200) ; % give your ranges
[f,qa] = meshgrid(f,qa) ; % for a mesh
y=@(f,qa)(31*f.^6)/49000000000 - (667*f.^2)/39200 - (657*f.^4)/98000000 - (375*cos(qa))/28 - (f.^2.*cos(qa))/400 + (3*f.^4.*cos(qa))/7000000 + 375/28;
y = y(f,qa) ;
contour(f,qa,y,[0 0])
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