How to replace a column vector in matrix

A =  [1 -4 1;4 -1 2;2 2 -3]

B = [6;-1;-20]

I want to replace part of matrx A i.e (1 -4 1) with B.

How can I do this?

Thank you for your help.

[Stephen23]

"How can I do this? "

Basic indexing (just the the introductory tutorials show):

>> A = [1,-4,1;4,-1,2;2,2,-3]
A =
    1   -4    1
    4   -1    2
    2    2   -3
>> B = [6;-1;-20];
>> A(1,:) = B
A =
    6   -1  -20
    4   -1    2
    2    2   -3

[kelly lim]

how do you set the name of the new matrix , instead of A can you change it to Ax without changing the name of the original matrix. Please demosntrate thank you

Answer 1

[Sara Boznik]

A =  [1 -4 1;4 -1 2;2 2 -3]
B = [6;-1;-20]

B=B'
A(1,:)=B'

[James Tursa]

You don't actually need to do any transposing. Just using B directly works, even though B is a column vector and you are assigning it to a row:

A(1,:) = B;

[Danny Maefengea]

Thank you Sir

[kelly lim]

how do you set the name of the new matrix , instead of A can you change it to Ax without changing the name of the original matrix. Please demosntrate thank you

[Phuwanut Pataratawinun]

If you want changed matrix Ax without changing matrix A, just copy the contents of matrix A over to a new matrix Ax, then do the same replacement.

A =  [1 -4 1;4 -1 2;2 2 -3]
B = [6;-1;-20]
B = B'

Ax = A

Ax(1,:) = B'