Error: A null assignment can have only one non-colon index

% I have this code
for i=1:40
SSS(i,1)=1
end
for j=1:20
zz(i)=0.25;
SSS(end+1,1)=ZZ(i);
end
[index idx]=find(SSS==1);
SSS(:,2)=SSS(:,1);        % values in second column for Ref
% now want to delete first 10 column of 1 in second column only, and add new rows at the end with value 0.5
       for j=1:10
           SSS(index(j),2)= [];    % if I do here NaN then it will increase the size of array, that i Dont want to do
           SSS(end+1,2) =0.5;
       end 
       
%% my final ans should be as per attached ans.mat file

[KSSV]

You cannot remove elements from matrix like that.

[mukesh meharda]

Then what will be the solution to delete the element and add new data at the end of that column ?

[mukesh meharda]

Is there any solution to convert this into cell format and then after the operation, convert back to matrix/array format?

[KSSV]

A = rand(10,2) ; 
A(1,:) = []   % you can remove a row
A(1,1) = []   % you cannot remove an element 

What you expect?

[mukesh meharda]

I want to remove element and then shift 2nd column data upward and add new data at the end only

[KSSV]

Okay so remove the entire...