How to fill a cell with function handles using iteration numbers?

8 views (last 30 days)
I am trying to create N functions that are all extremely similar, except they use different constants from an N sized array.
I have a cell G = {}, but I'm not sure how to create a for loop that would set G{1} = @(x) c(1)*x (this is an example, not the actual function), where c is an array containing the constants cooresponding to each function.
I tried placing G{k} = @(x) c(k)*x and iterating k from 1 to N, but that creates functions that contain k, and not the actual iteration number 1, 2,...N.

Accepted Answer

Steven Lord
Steven Lord on 5 Aug 2020
c = (1:10).^2;
G = cell(size(c));
for whichElement = 1:numel(c)
G{whichElement} = @(x) c(whichElement)*x;
end
Yes, when you display each element of G the expression that gets displayed will include whichElement. But the anonymous function remembers the value whichElement (and c for that matter) had when it was defined and will use those values when the anonymous function is evaluated.
G{7}(5) % 49*5 = 245

More Answers (0)

Categories

Find more on Loops and Conditional Statements in Help Center and File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!