How to solve the following error : "Maximum number of function evaluations exceeded; increase OPTIONS.MaxFunEvals".

I need to maximize the objective function y = exp(x) using 'fmincon' and a -ve sign in the objective function.I have used upper & lower bounds of x as 300 and 400. When I run with y=exp(x), I get the error: Maximum number of function evaluations exceeded;

 increase OPTIONS.MaxFunEvals.

When I run for y = exp(-x), I get the error:

Optimization terminated: first-order optimality measure less than options.TolFun and maximum constraint violation is less

 than options.TolCon.
Active inequalities (to within options.TolCon = 1e-006):
  lower      upper     ineqlin   ineqnonlin
    1

The code is :

function xout = s1

%---------------------------optimization-------------------

x0 = [300]; % Just some Initial Condition

ub = [400]; % Upper bounds

lb = [300]; % Lower bounds

F = @(x) obj(x);

xout = fmincon(F,x0,[],[],[],[],lb,ub); %optimization operator

function obj = obj(x)

y = exp(x)

obj = -y

end

end

Please help me as to how I can remove this error. Thanks.

Answer 1

[Walter Roberson]

options = struct('MaxFunEvals', 2000);
xout = fmincon(F, x0, [], [], [], [], lb, ub, options);

[Nitin Samuel]

Thanks Mr.Roberson.But I just tried that and got the following error:

??? Error using ==> optimfcnchk at 287 NONLCON must be a function.

Error in ==> fmincon at 302 [confcn, msg] = optimfcnchk(NONLCON,'fmincon',length(varargin),funValCheck,gradconstflag,false,1);

Error in ==> site at 12 xout = fmincon(F, x0, [], [], [], [], lb, ub, options);

[Walter Roberson]

xout = fmincon(F, x0, [], [], [], [], lb, ub, [], options);

OR

xout = fminbnd(F, lb, ub, options);

[Nitin Samuel]

Thanks Mr.Roberson. I tried and it shows following error:

Maximum number of iterations exceeded; increase OPTIONS.MaxIter.

I have added "options = struct('MaxIter',2000);"

Still it shows the same...

[Nitin Samuel]

Thank you Mr.Roberson!! It works so perfectly!!