handle character minus character

I have two characters which contain '18:29:42.835' and '18:29:49.425'. How is it possible to subtrack t2-t1 so as to find duration?

 Accepted Answer

f = @(x) str2double(regexp(x,':','split'));
t1 = num2cell(f(t1)); % where t1 & 2 are your char arrays
t2 = num2cell(f(t2));
Wanted = duration(t2{:})-duration(t1{:})

1 Comment

f = @(x) str2double(regexp(x,'\D','split'));
t1 = num2cell(f(t1));
t2 = num2cell(f(t2));
Wanted = duration(t2{:})-duration(t1{:});
Wanted.Format = 'hh:mm:ss.SSSS'

More Answers (1)

Walter Roberson
Walter Roberson on 10 Jul 2020
If you have a recent enough MATLAB version, pass the character vectors to duration() and then subtract one from the other.
If your MATLAB is a bit older, then you will need to split the vectors at the colons, then str2double() to get the individual components, and pass those to duration.
Or you could use sscanf() with a format of '%f:%f:%f' to get the numeric components and pass those to duration()

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Asked:

on 10 Jul 2020

Locked:

on 13 Jan 2025

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