Building a matrix inside a for loop

Hi guys, can anyone help me with this please. Thanks.
So i have this Excel file. I filtered a column and then did some operations on the filtered data .
in the end, I wanna create a new matix, A, with the following characteristics. The matrix should have dimension: partID rows* 5 columns. First colum should contain the partID number (from 3 to 15), second column should contain the value of M associated with the partID, third column S, fourth m and fifth s.
how do i build A inside the cycle?

6 Comments

Can you share the file?
thanks you, Here is the file excel.
Murstoe, it's bad form to remove your question after being given an answer. Can you put it back?
Original question from Google Cache:
"Building a matrix inside a for loop"
Hi guys, can anyone help me with this please. Thanks.
So i have this Excel file. I filtered a column and then did some operations on the filtered data .
in the end, I wanna create a new matix, A, with the following characteristics. The matrix should have dimension: partID rows* 5 columns. First colum should contain the partID number (from 3 to 15), second column should contain the value of M associated with the partID, third column S, fourth m and fifth s.
how do i build A inside the cycle?
xlsData = xlsread('PartS_all.csv');
partID=xlsData(:,4);
for partID=3:15
tenpm=xlsData(xlsData(:,4)==partID,:);
part=sortrows(tenpm, 2); %Sort second column
M(partID)=mean(part(:,8));
S(partID)=std(part(:,8));
m(partID)=mean(part(:,11));
s(partID)=std(part(:,11));
A=
end
Guys I’m so sorry I don’t know what happened to it. I will sure fix it. I apologise again
(Answers Dev) Restored edit

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 Accepted Answer

Turlough Hughes
Turlough Hughes on 16 May 2020
Edited: Turlough Hughes on 16 May 2020
You could do it as follows:
xlsData = xlsread('PartS_all.xlsx');
partID = xlsData(:,4);
uPartID = unique(partID).'; % Unique part IDs
% Preallocate space
c = 0;
A = zeros(numel(uPartID),5);
for currPartID = uPartID
c = c+1;
part = xlsData(xlsData(:,4) == currPartID,:); %edit
A(c,:) = [currPartID mean(part(:,8)) std(part(:,8)) mean(part(:,11)) std(part(:,11))];
end

2 Comments

I get the following error:
Index in position 2 exceeds array bounds (must not exceed 1).
Error in Untitled (line 25)
A(c,:) = [currPartID mean(part(:,8)) std(part(:,8)) mean(part(:,11)) std(part(:,11))];
I made a mistake. It should work fine now.

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