How to Repeat the script and determine if user input is Binary.

Hey guys, new to matlab and im having an issue trying to loop the script.

dec = 0;
base = 1;    
bin = input('Enter a binary number:');
while bin >= 1
    rem = mod(bin,10);
    dec = dec + (rem * base);
    bin = round(bin / 10);
    base = base * 2;
    
end
disp(dec)

Thats my script. Its function is to convert binary numbers into decimal numbers which it does successful. But i need it to keep repeating (asking for user input) until an illegal number is inputted (anything other than 0 or 1). However when run this script just ends.

Also need help on displaying "not a binary number" if non binary number are inputted thanks

Answer 1

[Walter Roberson]

If you need to keep repeating asking for input, then you need another while loop around what you have. The while loop can be

while true

since you want it to repeat forever.

Also need help on displaying "not a binary number" if non binary number are inputted thanks

In such a case, rem would not be either 0 or 1.

ps: watch out for negative numbers.

[Faris Haroon]

Thank you very much, putting a while loop around the whole script fixed my issue. However im still unable to filter out non-binary numbers as it still generates an output for non binary numbers. Thanks

[Walter Roberson]

When you find a non-binary number, you should probably tell MATLAB to stop the loop.

Hint: if you stop the loop early, then bin>=1 will still be true after the loop, and if you detect that case then you would refrain from doing the disp()... and you would also want to exit the while true

Answer 2

[Mehmed Saad]

• regexp to find if number is between 2-9, if there exist any number, break the while loop

while(1)
bin = input('Enter a binary number:');    
dec = 0;base = 1;    
if(isempty(regexp(num2str(bin),'[2-9]', 'once')))
while bin >= 1
   
    rem = mod(bin,10);
    dec = dec + (rem * base);
    bin = round(bin / 10);
    base = base * 2;
end

disp(dec);

else
 break;
end
end
disp('Not a valid input');