# Reordering string arrays if string is >9

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Jason on 18 Mar 2020
Commented: Jason on 18 Mar 2020
Hello, I have a string array that has been sorted but puts 10 next to 1
b =
1×6 string array
"1" "10" "3" "5" "7" "r1"
My strings are upto 12.
I want the last element to remain where it is, and to move any strings > 9 if exist to the end -1
i.e.
"1" "3" "5" "7" "10" "r1"
and if I have
"1" "10" "12" "5" "7" "r1"
then to be
"1" "5" "7" "10" "12" "r1"
This is my attempt:
b
Id10 = find(contains(b,"10"))
if Id10>0
e=b(Id10); b(Id10)=[]; b(end-1)=e;
out{j,1}=b;
b
end
Id11 = find(contains(b,"11"))
if Id11>0
e=b(Id11); b(Id11)=[]; b(end-1)=e;
out{j,1}=b;
b
end
Id12 = find(contains(b,"12"))
if Id12>0
e=b(Id12); b(Id12)=[]; b(end-1)=e;
out{j,1}=b;
end
b
but it seems to be over writing the end-1 element
b =
1×7 string array
"1" "10" "11" "12" "3" "6" "r1"
Id10 =
2
b =
1×6 string array
"1" "11" "12" "3" "10" "r1"
Id11 =
2
b =
1×5 string array
"1" "12" "3" "11" "r1"
Id12 =
2
b =
1×4 string array
"1" "3" "12" "r1"
Thanks for any help
##### 2 CommentsShowHide 1 older comment
Jason on 18 Mar 2020
Perfect, thankyou very much!

BobH on 18 Mar 2020
sort_nat is powerful, and has helped me several times.
An alternative for simple number/not-number values is straightforward
1. find the locations of the numbers
2. sort those
3. append the not-numbers
z = cellfun(@(X) logical(~isempty(str2num(X))),b); % z shows locations of number strings
n = cellfun(@str2num, b(z)); % into numerical
[~, ix] = sort( n ); % ix tells what order to pull from b
r = b(ix); % fill the result using sorted numbers
r{end+1} = b{~z}; % append the not-numbers
BobH on 18 Mar 2020
Just for completeness, for those who might have numbers anywhere, here's a more general solution
1. find the locations of the numbers
2. build a new numeric vector, using a placeholder number for the not-numbers. Inf or -Inf are good choices that will sort to the end or the front
3. use the sort index to pull from b
z = cellfun(@(X) logical(~isempty(str2num(X))),b); % z shows locations of number strings
n(~z) = Inf; % placeholder value; makes not-strings sort to end
n(z) = cellfun(@str2num, b(z));
[~, ix] = sort( n );
r = b(ix);

dpb on 18 Mar 2020
Jason on 18 Mar 2020
Thanks, but Im running into an error
b =
1×6 string array
"1" "3" "6" "8" "9" "r1"
Index in position 1 exceeds array bounds.
Error in sort_nat (line 62)
num_val(i,z(i,:)) = sscanf(sprintf('%s ',digruns{i}{:}),'%f');
Error in PlateSeq2JB/LockPositionsButtonPushed (line 693)
[b,~] = sort_nat(b)