how to extract n rows in a matrix column iteratively?

i have a matrix A(15,1) looking like this

    0.4218
    0.9157
    0.7922
    0.9595
    0.6557
    0.0357
    0.8491
    0.9340
    0.6787
    0.7577
    0.7431
    0.3922
    0.6555
    0.1712
    0.7060

I want to extract always 3 rows iteratively and put it in a cell,

In the first cell i want to have

    0.4218
    0.9157
    0.7922
    

in the second cell i want to have

    0.9595
    0.6557
    0.0357
   

and so on..., i would then end up with 5 cells as this {1,5}(3,1)

is there an easy way to do it without writing several for loops?

Thanks already in advance!

Answer 1

[James Tursa]

Depending on what you are doing downstream in your code, it may make more sense to simply reshape and then access the columns. E.g.,

B = reshape(A,3,[]);

then in your code use B(:,k) to access the k'th column

But if you really want/need the cell array approach then maybe something like this would suffice

B = mat2cell(A,3*ones(1,numel(A)/3));

[Kim Arnold]

Thanks a lot, gives me exactly what i need!

Answer 2

[Andrei Bobrov]

out = num2cell(reshape(A,3,[]),1);

or

out = accumarray(ceil((1:numel(A))'/3),A,[],@(x){x});

[Kim Arnold]

Thanks for your answers as well, i learned some new commands!