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My code won't run. It says there is an error in line 30.

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Oliver Mendoza
Oliver Mendoza on 20 Feb 2020
Answered: Alex Mcaulley on 20 Feb 2020
I am trying to make this program run. When I attempt to run it, it says that there is an error in line 30. I don't know what the issue could be.
  1 Comment
Jon on 20 Feb 2020
What does it say the error is? Please cut and paste the entire error message. Also, please post the code that you use to test/call your function that can be run to produce the error.

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Answers (1)

Alex Mcaulley
Alex Mcaulley on 20 Feb 2020
There is an error in your calls to matlabFunction:
function [] = Newton(f, x1, tol, N)
% Newton uses Newton’s method to approximate a root of f(x) = 0.
% [r, n] = Newton(f, x1, tol, N), where
% f is a symbolic function representing f(x),
% x1 is the initial point,
% tol is the scalar tolerance for convergence (default 1e-4),
% N is the maximum number of iterations (default 20),
% r is the approximate root of f(x) = 0,
% n is the number of iterations required for convergence.
if nargin < 4 || isempty(N), N = 20; end
if nargin < 3 || isempty(tol), tol = 1e-4; end
% Find f' and convert to MATLAB function for evaluation
% syms x
fp = matlabFunction(diff((f))); %Changed
% Convert f to MATLAB function for evaluation
% syms x
f = matlabFunction(f); %Changed
x = zeros(1,N+1); % Pre-allocate
x(1) = x1;
for n = 1:N
if fp(x(n)) == 0
r ='failure';
x(n+1) = x(n) - (f(x(n))/fp(x(n)));
if abs(x(n+1) - x(n)) < tol
r = x(n+1);

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