calculating mean values of a 3D matrix

hi.

I have a 3D matrix. size 79x63x100

I want to calc the mean of each of the 79x63 values so to get a 2D matrix the size of 79x63x1

but when i do mean(mat) i get it in the size of 1x63x100

how should I write it?

Thanks, Noa

[Deepak Singh]

You can mention the dimension you want to take mean across. Something like this will work: x=mean(mat,3);

[ankit patel]

its not working if i change the value 3 with more than 3 in your equation.

Answer 1

[Andrei Bobrov]

out = mean(yourarray3D,3)

[Thumree Sarkar]

What if I want to make a 2D matrix out of (mxnxp) 3D matrix, but the mean is to be done for the n th component instead of p th?

[Andrei Bobrov]

out = squeeze(mean(yourarray3D,2));

[LarsFM]

I try to calclulate standard deviation with the same method:

 out = std(yourarray3d,3);

But its not working in the same way as with the mean. What can I do to make it work?

[Akshay Bhardwaj]

    out = std(yourarray3d,[],3)

[BBB]

Hi,

I also have a similar question.

I have a 51x51 2D matrix that I need to take a mean off, but it has to give me back a 51x51 2D matrix as an output.

How can do this using the mean function. I need to put this in a loop as well. Please see code below for reference:

rand_image_stim = rand(10000,51,51);
kk = 1:length(rand_image_stim);
firing_rate_kk(kk) = 0;
gab_filt = z_cos.*z_gauss;
lp(kk) = 0;
for kk = 1:length(rand_image_stim)
    output_kk = squeeze(rand_image_stim(kk,:,:)).*gab_filt;
    firing_rate_kk(kk) = sum(output_kk,'all');
    jk = squeeze(rand_image_stim(kk,:,:))*firing_rate_kk(kk);
    lp = squeeze(mean(jk,2)); %Need help with this last bit!
end

Answer 2

[Zoe]

shape2 = reshape(yourarray,[100 79*64]);
meanArray = mean(shape2,2);