Isolate Digits in a number

Take c input as 
c= 0010100101100

Note: Please don't take c as char

isolate each digit into index of "nary"

i.e.,

>> naray =
  0 0 1 0 1 0 0 1 0 1 1 0 0

i.e.,

nary(1)=0
nary(2)=0
nary(3)=1
nary(4)=0
nary(5)=1
nary(6)=0
nary(7)=0
nary(8)=1
nary(9)=0
nary(10)=1
nary(11)=1
nary(12)=0
nary(13)=0

[David Young]

Could you say why you want to do this, please? I ask because it looks a bit like it could be a homework problem. Also, is it assumed that nary is to have 13 elements? The number of leading zeros in 0010100101100 is lost, of course, so there's no information in c about how many leading zeros are to be stored in nary.

Answer 1

[Matt Fig]

If c is not a char, then what is it? How could you even enter c in MATLAB if it is not a char? You will lose the leading zeros if c is not a char.

>> c = 0010100101100
c =
    10100101100

Answer 2

[Paulo Silva]

So if c isn't char it could be a vector:

nary='0010100101100' - '0'; %create the vector with the data provided
%now you can call each value from 1 until 13
nary(1)
nary(2)
nary(3)
nary(4)
nary(5)
nary(6)
nary(7)
nary(8)
nary(9)
nary(10)
nary(11)
nary(12)
nary(13)

[Raviteja]

Your answer working! Thanks!

Answer 3

[David Young]

Well, since Matt's answer has been accepted (!), I guess I might as well offer mine, for non-char input:

nary = floor(c*10.^(-13:0))-10*floor(c*10.^(-14:-1));

[Walter Roberson]

Ah, but it doesn't handle negative binary numbers ;-)

If you change the floor() to fix() then for negative c, each of the 1 values will come out negative, which would arguably be a fair solution.

[David Young]

Indeed!

Answer 4

[Walter Roberson]

nary = sprintf('%d',c) - '0';

Subject, though, to the problems the others noted about losing leading zeros.

Note: this solution is also not valid if there are more than 53 bits from the first 1 in the number.