How to prevent addition from showing up in command window

I ran some code and am having trouble with the results of the code come out like this:

995

996

997

998

999

1000

How do I just get 1000 instead of all of the numbers? I have suppressed literally everything in the code.

[stozaki]

Hello Kyle,

I don't know your code. So, as a guess, can't you deal with using "end"?

end as Object Index

Regards,

stozkai

[Rik]

Without a meaningful sample of your code, we can't give a meaningful solution.

[Stephen23]

Kyle Donk's "Answer" moved here:

N=10;
 error=1;
while error>10^-4
N=N+1;
total=0;
    for n=1:N;
        y=1/n^2;
        total=total+y;
    end
    error=((pi^2)/6)-total;
    disp(N)
end

Answer 1

[stozaki]

If you get only 1000, you can try following script.

N=10;
 err=1;
while err>10^-3
N=N+1;
total=0;
    for n=1:N
        y=1/n^2;
        total=total+y;
    end
    err=((pi^2)/6)-total;
    
end
disp(N);

Is the intent of the question I understood fit?

 

Regards,

stozaki

[Image Analyst]

Built in function names, like error and sum, should not be used as variable names.

Also not sure why you're printing out the iteration number in

fprintf('>> error value %d is over 10^3\n',N);

instead of the final error.

[stozaki]

It was just a descriptive print statement. I'm sorry. I also prioritized leaving the questioner's code as much as possible.

Answer 2

[Image Analyst]

Try this:

numberOfTerms = 10;
maxIterations = 1000000; % To prevent infinite loops.
loopCounter = 1;
theError = 1;
while theError > 1e-4 && loopCounter < maxIterations
	total = 0;
	for n = 1 : numberOfTerms
		y = 1 / n^2;
		total = total+y;
	end
	theError = ((pi^2)/6) - total;
	% Optional: print out the total and error at each iteration.
	fprintf('After %d iterations, and using %d terms, the total is %f, and the error is %.9f.\n', ...
		loopCounter, numberOfTerms, total, theError);
	numberOfTerms = numberOfTerms+1;
	loopCounter = loopCounter + 1;
end
% Print out the final results.
fprintf('The final error after the loop exited is %.9f.\n', theError);

You'll see

After 9989 iterations, and using 9998 terms, the total is 1.644834, and the error is 0.000100015.

After 9990 iterations, and using 9999 terms, the total is 1.644834, and the error is 0.000100005.

After 9991 iterations, and using 10000 terms, the total is 1.644834, and the error is 0.000099995.

The final error after the loop exited is 0.000099995.