Ascending table column labels

Hello all,

I've got a table which contains 38 column's, each representing one cycle. I want to label them "cycle 1", "cycle 2", etc.

I tried something like this, but this doesn't work. Any help would be appreciated, thank you!

colnames = "Cycle" + 1:size(matrix,2);
table = array2table(matrix,'VariableNames', colnames);

Answer 1

[Star Strider]

Use the compose function (R2016b and later versions):

colnames = compose("Cycle %d", 1:size(matrix,2));

Alternatively, use the sprintfc (undocumented) function:

colnames = sprintfc("Cycle %d", 1:size(matrix,2));

No loop necessary.

[Joost de Witte]

Thank you, it worked.

[Star Strider]

As always, my pleasure!

Answer 2

[Jesus Sanchez]

I would do it inside a for loop:

matrix = [1 2 3; 3 4 5; 6 4 5; 9 8 7]; % 4 rows and 3 columns
colnames = {}; % Initializes colnames
for n=1:size(matrix,2)
    colnames{end+1} = ['Cycle ' num2str(n)];
end
colnames = colnames.'; % To put them in one column, for readability

Result:

ans =

3×1 cell array

{'Cycle 1'}

{'Cycle 2'}

{'Cycle 3'}

[Joost de Witte]

Thank you, did worked!