Creating a For loop for a Harmonic Series

function x = HarmArray(last)

x=zeros(1,last);

for i=1:last

x(i)=1./last(i)

end

end

Keeps giving me this error:

''Index exceeds the number of array elements (1).''

Error in HarmArray (line 4)

x(i)=1/last(i)

[Douglas Brunson]

I suspect that 'last' is an integer.

[Douglas Brunson]

Hence, 'i' can only be one.

Answer 1

[David Hill]

last is not an array; therefore last(i) does not work!

function x = HarmArray(last)
x=zeros(1,last);
for i=1:last
    x(i)=1/i;%this should give you what you want
end
end

Alternatively, you would not need to use a loop.

x=ones(1,last)./(1:last);
h=cumsum(x);%provides harmonic series (1.0000    1.5000    1.8333    2.0833    2.2833    2.4500  ...)

[Leonardo Morales]

Understood. Thank you both!