How to reshape every cell in a structure

Hi,

I am trying to reshape every cell in a 1x4 structure with 10 fields. A simplified example would look like this but when I try to reshape every 1x48 cell into 4x12 cells I get the following error: Inputs to STRUCTFUN must be scalar structures.

b = struct('a', {[1:48], [1:48], [1:48], [1:48]})

structfun(@(a) reshape(a, 12, 4), b, 'UniformOutput', false)

Thoughts ?

Answer 1

[madhan ravi]

arrayfun(@(x) reshape(b(x).a, 12, 4), 1:numel(b), 'UniformOutput', false)

[madhan ravi]

Note: You’re reshaping them into 12 X 4 to make it 4 X 12 just swap 12 and 4.

[Blue]

This works great for one field (in this case a) but lets say I have 10 fields. How do I apply this to all fields ?

[madhan ravi]

If you have different named fields for example, then looping through fieldnames is one option. If it’s a(1) ,a(2) and so on again looping should do the trick.

[Blue]

Mmmm, something like this ?

b = struct('a', {[1:48], [1:48], [1:48], [1:48]})

fn = fieldnames(b);
for k = 1:length(fn)
    j = char(fn(k))
    b = arrayfun(@(x) reshape(b(x).j, 4, 12), 1:numel(b), 'UniformOutput', false)
end

[madhan ravi]

fn = fieldnames(b);
for k = 1:numel(b)
    for l = 1:numel(fn)
    b(k).(fn{l})= reshape(b(k).(fn{l}), 4, 12);
    end
end

[Blue]

Great, thank you.