How to supplement the matrix?
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Hello! I cleaned my signal from emissions, it is in the form of a matrix, but there I used i-1, in consequence of which, instead of 1100, I now have 1099 values, how can I add the last value?\
for i = 1:length(d)-1 % Error 1100 1099
if g(i)-50>= g(i+1);
f(i)=g(i);
end
end
6 Comments
Your question is not very clear, but possibly you should preallocate the output array:
Lev Mihailov
on 5 Jul 2019
Image Analyst
on 5 Jul 2019
How do c and Matrix relate to f and g?
DId you try Stephen's suggestion of putting
f = zeros(size(g));
before your original for loop?
@Lev: I do not see the relation between
if g(i)-50>= g(i+1);
and
if c (i) + 10 > size (Matrix, 1)
Which problem do you want to solve? What about:
f = g(diff(g) < -50)
instead of the loop?
Lev Mihailov
on 5 Jul 2019
Jan
on 8 Jul 2019
@Lev: |zeros()< does not convert anything to zeros. Please read the documentation:
doc zeros
to find out, that this is a pre-allocation of the output. Letting an array grow iteratively is extremely inefficient. Matlab has to allocation a new array in each iteration. So:
r = [];
for k = 1:1e6
r(k) = rand;
end
needs 8*1e6 bytes finally, but intermediately 8*sum(1:1e6) bytes are allocated: 4 TeraByte!
I do not understand the meaning of your comment. If you detect outliers by subtracting pairs elements, of course there is one element less in the output.
Answers (2)
dpb
on 5 Jul 2019
Adding to Stephen's answer Matlab syntax, the crystal ball says
for i = 1:length(d)-1 % Error 1100 1099
if g(i)-50>= g(i+1);
f(i)=g(i);
end
end
becomes
f=zeros(size(g));
ix=diff(g)<-50;
f(ix)=g(ix);
Lev Mihailov
on 5 Jul 2019
0 votes
5 Comments
Lev Mihailov
on 5 Jul 2019
dpb
on 5 Jul 2019
- We can't see your terminal -- an error out of context with code that produced it is meaningless...paste the entire red text and the preceding code line that produced the error.
- You can always augment an array, yes, but you have to do so by a form that is allowable catenation, not by reference outside an existing array bounding.
The code I gave cannot produce an indexing array bounds error...and will have resulting array f of same size as g
Lev Mihailov
on 5 Jul 2019
Edited: dpb
on 5 Jul 2019
dpb
on 5 Jul 2019
c can only have length(d)-1 elements in it...as has been said multiple times before, preallocate it to the size wanted or compensate that there will always be one less array element since you're dealing with diff() functionality that produces one less element by its very nature.
In
for chek = 1:length(d)-1
if g(chek )-50>= g(chek +1);
c(chek )=10;
else g(chek )+50 <= g(chek +1);
c(chek)=g(chek );
end
end
the else clause should be elseif it appears.
What is the value for c if abs(diff(g))<50?
Again, use Matlab array syntax; the above loop construct (presuming the "elseif" and zero for then missing "else" clause)
c=zeros(size(g)); % preallocate to same size as g array
ix=diff(g)<-50;
c(ix)=10;
ix=diff(g)>=50;
c(ix)=g(ix);
You need to define what happens in the other cases not satisfied...if they're to remain unchanged, then use
c=g;
for initialization instead of zeros
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