Result producing 1x5 array instead of 10x5?

Hi all,

I have the following code which I'm expecting to produce a 10x5 array but it's only giving me a 1x5, and I'm not sure why?

n = 10;
result = zeros(n,5);
for k=1:n;
A0=1;P0=29;g=rand;p=rand;B=rand;
result = [A0,P0,g,p,B];
end;

Alternatively, if I write the code this way I get a 10x1 cellular array, each entry of which represents a 1x5 numeric array. This gives me the number of results I want, but not in the format I'm looking for (which, again, is ultimately a 10x5 array). Thanks in advance!

n = 10;
result = cell(n,1);
for k=1:n;
A0=1;P0=29;g=rand;p=rand;B=rand;
result{k} = {A0,P0,g,p,B};
end;

Answer 1

[Alex Mcaulley]

You need to specify the index:

n = 10;
result = zeros(n,5);
for k=1:n;
A0=1;P0=29;g=rand;p=rand;B=rand;
result(k,:) = [A0,P0,g,p,B];
end;

[Thomas Veith]

Thank you so much, that worked perfectly!

[Alex Mcaulley]

By the way you can do it without loop:

n = 10;
A0=1;P0=29;g=rand;p=rand;B=rand;
repmat([A0,P0,g,p,B],n,1)

[madhan ravi]

That would just copy the same g p B values through repmat() so creating n elements for g p B and then copying it into the matrix would be better.

[Alex Mcaulley]

Yes, as @madhan said, if you want random numbers for all rows:

n = 10;
A0=1;P0=29;
result = [repmat([A0,P0],n,1),rand(n,3)]

Answer 2

[Rob L]

Your first method overwites the result every loop with a [ 1 x 5 ] array.

You could (among many other solutions) use:

n = 10;

result = zeros(n,5);

for k=1:n

A0=1;P0=29;g=rand;p=rand;B=rand;

result(k,1) = A0;

result(k,2) = P0;

result(k,3) = g;

result(k,4) = p;

result(k,5) = B;

end