Help counting a string of 1s in 2018a?

I want to write a function that will detect and count the number of strings of consecutive 1's in a vector.

For example, if I have a vector of [01110011100], I am looking for a function that will give me an answer of 2, as there are 2 strings of consequetive 1s

Answer 1

[Raj]

You can use something like this:

A=[0 1 1 1 0 0 1 1 1 0 0]
A1 = [1,diff(A)]~=0;
Count = [A(A1)'];
Required_Answer=sum(Count(:) == 1)

[friendlylouie]

Thanks very much!