How to store matrix whose dimension is changing in each iteration ?

hello all

How to store matrix whose dimension is changing in each iteration?

can anyone expalin with example?

Answer 1

[KALYAN ACHARJYA]

Cell array

result=cell(1,iter);
for i=1:iter
%say matrix1 have changes the dimention in each iteration
% do operation, say matrix1 is the result in this iteraion.
result{i}=matrix1
end

Exampele:

>> A=rand(2,4)
A =
    0.9324    0.2304    0.8681    0.9226
    0.2963    0.1660    0.2219    0.9020
>> B=magic(3)
B =
     8     1     6
     3     5     7
     4     9     2
>> result={A,B}
result =
  1×2 cell array
    {2×4 double}    {3×3 double}
>> 

[madhan ravi]

Don’t forget to preallocate!

[Manoj Kumar]

it's not working.

[KALYAN ACHARJYA]

Where is the issue, can you share?

As per your question>>

How to store matrix whose dimension is changing in each iteration ?

Best way Celll Array (Alreadt shown the example too)

>> A=rand(2,4)
A =
    0.9324    0.2304    0.8681    0.9226
    0.2963    0.1660    0.2219    0.9020
>> B=magic(3)
B =
     8     1     6
     3     5     7
     4     9     2
>> result={A,B}
result =
  1×2 cell array
    {2×4 double}    {3×3 double}
>> 

Here we have saved the two matrix having sizes 2x4 and 3x3 in result cell array.

Answer 2

[Raj]

Use cell array

for i = 1:10
     A = rand(i,i) % A size is changing with every iteration
     B{i} = A; % Store A as cell
end
Required_matrix=cell2mat(B(1,10)) % Suppose I want to extract the 10th iteration matrix

[Manoj Kumar]

its working direcctly, but If we get A return from functioion then how wil to strore it.

e.g. [A, B] = function1(arg1, arg2).

Actually I trying to fix this issue.