Finding remaining numbers in logical indexing?

How would you find how many numbers in an array do not meet any of the previous conditions without using else if statements?

I want to return all the numbers that do not meet the previous conditions listed, but I can't figure out how to do that without using if else statements.

find=length<1;

disp('stubby')

sum(find(:) == 1)

find=(length < 3) & (max_width_head > mean_width_neck*2);

disp('mushroom')

sum(find(:) == 1)

find=max_width_head>=mean_width_neck;

disp('long thin')

sum(find(:) == 1)

[James Tursa]

You are really going to confuse your readers by using the names "find" and "length" as variable names ... they shadow important MATLAB functions. I would advise using different names.

[madhan ravi]

First and foremost your variable naming is totally a bad idea and second of all what is the input and what output are you expecting?

Answer 1

[James Tursa]

E.g.,

find1 = length<1;
    :
find2 = (length < 3) & (max_width_head > mean_width_neck*2);
    :
find3 = max_width_head>=mean_width_neck;
sum(~(find1 | find2 | find3))  % the number that don't match any of the previous conditions

[Holly Robinson]

That worked perfectly thank you so much!!