How to select desired row

I have a workspace A with value 81536x10 double. I want to take create new workspace from workspace A with row 1 to 112, 225 to 336, 449 to 560 and so on.

Answer 1

[Jos (10584)]

ix = [0:224:81563]' + 1:112 ; % calculate row indices
ix(ix>size(A,1)) = [] % remove row indices that are too larger
A2 = A(ix, :) % a single array

Alternatively, you can store each section in a cell array

A3 = arrayfun(@(k) A(k:k+111, :), 1:224:81563, 'un', 0) % no check of indices

[Setiadi Suriana]

Thank you for answer, but from that code, i only can get row 1-112 only but i want another rows 225 to 336, 449 to 560 and so on (until 81536)

[Jos (10584)]

My code does that doesn't it? I suggest you come up with a smaller example, giving the input and expected output, for instance for a 10-by-2 array A.

[Setiadi Suriana]

I tried with 6 by 2 array A and want to obtain values from rows 1-2 and 5-6 but the output only rows 1-2

[Jos (10584)]

Oh, this might be related to your version of ML.

A = randi(100,6,2)
ix = bsxfun(@plus,[0:1]', 1:4:size(A,1))
A(ix,:)

should return rows 1-2 and rows 5-6 of A

[Setiadi Suriana]

Thank you, now it is working