find row with certain value and put in cell

B=[ 1     2
     1     5
     2     3
     2     4
     2     5
     3     4
     4     5
     4     7
     4     9
     5     6
     6    11
     6    12
     6    13
     7     8
     7     9
     9    10
     9    14
    10    11
    12    13
    13    14];
A= [1     0     1     0     1     0     1
     1     0     1     0     1     0     1
     0     1     0     0     0     0     0
     0     1     1     0     1     0     1
     1     0     0     0     0     0     0
     0     1     0     0     0     0     0
     0     0     1     0     0     0     0
     0     0     0     1     0     0     0
     0     0     0     1     1     0     1
     0     0     0     0     1     0     1
     0     0     0     0     1     0     0
     0     0     0     0     0     1     0
     0     0     0     0     0     1     1
     0     0     0     0     0     0     0
     0     0     0     1     0     0     0
     0     0     0     0     1     0     0
     0     0     0     0     0     0     1
     0     0     0     0     1     0     0
     0     0     0     0     0     1     0
     0     0     0     0     0     0     1];
 res=cell(1,size(A,2));
for i=1:size(A,2)
    [row,~]=find(A(:,i)==1);
    res{i}=B(row,:);
    
end
result= cellfun(@(x) unique(x),res,'UniformOutput',false);

I want to get this result={[1,2,5],[2,3,4],[1,2,4,5],[4,7,9],[1,2,4,5,6,9,10,11],[6,12,13],[1,2,4,5,6,9,13,14]}

Answer 1

[Jos (10584)]

result = arrayfun(@(k) unique(B(A(:,k)==1,:)).', 1:size(A,2), 'un', 0)

Answer 2

[adi kul]

Change last line to this:

result= cellfun(@(res) unique(res),res,'UniformOutput',false)

And let us know if this is what you were looking!

Answer 3

[Andrei Bobrov]

z = B.*permute(A,[1,3,2]);
[~,jj] = ndgrid(1:size(A,1)*2,1:size(A,2));
out = accumarray(jj(:),z(:),[],@(x){unique(x(x~=0))});