How to linearly change values in matrix

Observe this matrix:

thismatrix = eye(5)
thismatrix =

 1     0     0     0     0
 0     1     0     0     0
 0     0     1     0     0
 0     0     0     1     0
 0     0     0     0     1

I wish to replace the zeros on either size of the 1's on every row with values descending from 1 by 0.1.

This is what I want:

thismatrix = 

1.0000    0.9000    0.8000    0.7000    0.6000       
0.9000    1.0000    0.9000    0.8000    0.7000    
0.8000    0.9000    1.0000    0.9000    0.8000   
0.7000    0.8000    0.9000    1.0000    0.9000    
0.6000    0.7000    0.8000    0.9000    1.0000   

How can I accomplish this without numerous "for loops"/spaghetti code (especially if my matrix is larger)?

Answer 1

[Andrei Bobrov]

toeplitz(1:-.1:.6)

or

1 - abs((1:5) - (1:5)')*.1

[Hanna Haponenko]

Thank you kindly, Andrei