how to filling a matrix

how to fill a matrix of size 180 * 180 by results obtained by another program knowing that I will go through the matrix in a way 4 * 4 example

The first box must be filled by 3 values of 1 and a 0 by the following four boxes by 2 values of 1 and two values of 0, the following four values a value of 1 and a value of 0, and so on. at the end of the matrix 180 * 180

note: the number of values of 1 and 0 is the output of another program and it is the program entry that I am developing it

Resulat=[1,0,1,1,0.0,.........

1,1,0,0.0.1,..........]

[KSSV]

A = rand(4)>=0.5 ;

[dakhli mohamed]

how do I do with a matrix size 180 * 180 and thanks in advance

[dakhli mohamed]

[dakhli mohamed]

thank you for you KSSV

Answer 1

[Image Analyst]

Well you could use blockproc() to march along the data one element at a time and replacing the output block with the number of zeros specified in the input block in random locations. This requires the Image Processing Toolbox. Essentially it's

outputMatrix = blockproc(outputMatrix,[windowSize windowSize], myFilterHandle)

A full demo is attached.

A =

4 2 1 4 1

4 4 4 2 4

1 3 3 4 2

1 4 4 4 2

outputMatrix =

1 1 1 1 0 0 1 1 0 0

1 1 0 0 0 1 1 1 0 1

1 1 1 1 1 1 0 1 1 1

1 1 1 1 1 1 1 0 1 1

1 0 1 1 1 1 1 1 1 1

0 0 1 0 0 1 1 1 0 0

0 0 1 1 1 1 1 1 0 1

1 0 1 1 1 1 1 1 1 0

Note how each 2x2 block of the output array has as many 1's in it as the corresponding number in the input array A.

[dakhli mohamed]

I tried with this matrix (attached) but still the same problem

[Image Analyst]

Looks like it worked to me. Code is attached and figure is below. Exactly why do you say you have any problem. Is it because you said "I have an array of size 95 * 95 pixel each pixel contains a value either (1 or 2 or 3 or 4)" when your array actually has values 0,1, 2, and 3? My code doesn't care. It will work regardless as long as the numbers are less than the number of elements in the block. So what's the problem?

[Image Analyst]

Dakhli's "Answer" moved here:

thank youuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu so much

[dakhli mohamed]

Thank youuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu so much

Can I ask you another question please?

I want to save the result matrix in a variable so that I use it later.

How do I do that?

[Image Analyst]

It already IS saved in a variable called outputMatrix.

If you want to store it to a file on disk that another program can read in, you can use save():

fileName = fullfile(pwd, 'outputMatrix.mat')
save(fileName, 'outputMatrix');

then, in the other program use load():

s = load(fileName);
outputMatrix = s.outputMatrix;

[dakhli mohamed]

thank you so much

Answer 2

[Omer Yasin Birey]

Hi dahkli, try this

result = eye(180);


for i = 1:numel(result)
    
    temp = rand>(0.25*mod(i,3));
    result(i) = temp;
end

[dakhli mohamed]

I have an array of size 95 * 95 pixel each pixel contains a value either (1 or 2 or 3 or 4)

I will eventually create another size array (190 * 190)

if the pixel contains a value of 1 so the four subpixel new array containing a 1 and 3 zeros

if the pixel contains a value of 2 so the new array contains 2 valeues of 1 and 2 values of 0

if the pixel contains the value 3 so the new array contains 3 value of 1 and a value of 0

if the pixel contains the value 4 so the new tab contains 4 values of 1 and zeros value of 0

exempl:

A=[1,3

2.4]

Result new array=[1.0 1,1

0,0 1,0

1.0 1,1

1,0 1,1]

the four sub-pixel to the left of the second array represents the first array pixel (A)

and in my ca the table A is of size 95 * 95

Help please !!!!!!!

[dakhli mohamed]

thank you for you Omer Yasin Birey