How i Calculate the average number of even numbers in an array?
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How i Calculate the average number of even numbers in an array?
If the array:
1.3700 1.2200 2.2000 2.2800
so the avarage:
1.9
because: (1.22+2.22+2.28)/3=1.9
How i do this?
1 Comment
KSSV
on 4 Dec 2018
Check your question properly....
(1.22+2.22+2.28)/3 = 1.90...
What do you mean by odd numbers here in the array?
Accepted Answer
More Answers (2)
Kevin Chng
on 4 Dec 2018
My answer is
Check the index of Even number first
a = [1.3700 1.2200 2.2000 2.2800];
index = mod(single(a*100),2)==0;
Calculate the mean value of Even Number in the array
mean(a(index))
5 Comments
tomer kapuri
on 4 Dec 2018
Kevin Chng
on 4 Dec 2018
How to get the counter of even numbers? You may try
nume1(index)
or
sum(index)
Bruno Luong
on 4 Dec 2018
sum is correct numel is not
tomer kapuri
on 4 Dec 2018
Kevin Chng
on 4 Dec 2018
Edited: Kevin Chng
on 5 Dec 2018
Ya, numel is calculating the number of element. Sorry for my mistake.
However, tomer kapuri, any difficulties you are facing since you say something is not working.
Gareth
on 4 Dec 2018
Hi Tomer,
I am not sure if I understand your question correctly.
In MATLAB to calculate the average you would use the function: mean
In your example:
a = [1.37 1.22 2.20 2.28];
yourAverage = mean(a)
Please note in your question you asked about odd number. You could do:
mean(a(2:end))
This is adding the last 3 elements of the array a, and dividing by 3 as you illustrated, but there is something not right with your Maths... as:
(1.22+2.22+2.28)/3 is not 4.2.
Hope this helps.
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