How i Calculate the average number of even numbers in an array?

How i Calculate the average number of even numbers in an array?
If the array:
1.3700 1.2200 2.2000 2.2800
so the avarage:
1.9
because: (1.22+2.22+2.28)/3=1.9
How i do this?

1 Comment

Check your question properly....
(1.22+2.22+2.28)/3 = 1.90...
What do you mean by odd numbers here in the array?

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 Accepted Answer

a = [1.3700 1.2200 2.2000 2.2800];
ac = round(a*100);
mean(ac(mod(ac,2)==0))/100
result
ans =
1.9000

3 Comments

I thought of the same solution but didn't know to use round properly there ;-)
>>a=sprintf('%.32f\n',a.*100)
a =
'137.00000000000000000000000000000000
122.00000000000000000000000000000000
220.00000000000002842170943040400743
227.99999999999997157829056959599257
'
Here is what might happen if one does't take care about rounding
mod(1.12*100,2)==0
ans =
logical
0

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More Answers (2)

My answer is
Check the index of Even number first
a = [1.3700 1.2200 2.2000 2.2800];
index = mod(single(a*100),2)==0;
Calculate the mean value of Even Number in the array
mean(a(index))

5 Comments

thank you!!!
more question...how i can sum ther counter of even numbers?
How to get the counter of even numbers? You may try
nume1(index)
or
sum(index)
Ya, numel is calculating the number of element. Sorry for my mistake.
However, tomer kapuri, any difficulties you are facing since you say something is not working.

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Hi Tomer,
I am not sure if I understand your question correctly.
In MATLAB to calculate the average you would use the function: mean
In your example:
a = [1.37 1.22 2.20 2.28];
yourAverage = mean(a)
Please note in your question you asked about odd number. You could do:
mean(a(2:end))
This is adding the last 3 elements of the array a, and dividing by 3 as you illustrated, but there is something not right with your Maths... as:
(1.22+2.22+2.28)/3 is not 4.2.
Hope this helps.

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