How to save the for loop data

for x=1:0.5:20

how can store the value for this type of for loop.

[madhan ravi]

If you show the calculation we can vectorize it even without a loop if there is a possibility.

[wong loong]

for i=1:0.5:20

Base =(BaseValue.inputSingleScan-1.63)*(327/10)*100;

Top = (TopValue.inputSingleScan-1.63)*(327/10)*100;

PI1 = abs(Top - Base);

this is calculation.

[madhan ravi]

BaseValue.inputSingleScan ? provide the datas

[wong loong]

data scan from sensor.

[madhan ravi]

is it stored or live data?

[wong loong]

live data...i want store the data every time loop...then find out the maximun value.

Answer 1

[madhan ravi]

EDITED

x=1:0.5:20;
n=numel(x);
Base=cell(1,n); % PRE-ALLOCATION
Top=cell(1,n);
PI1=cell(1,n);
for i=1:n
    
        Base{i} =(BaseValue.inputSingleScan-1.63)*(327/10)*100;
        Top{i} = (TopValue.inputSingleScan-1.63)*(327/10)*100;
        PI1{i} = abs([Top{i}] - [Base{i}]);
end

values=[PI1{:}];
max_value=max(values);