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How to solve INDEX OUT OF BOUNDS ERROR? Please help me. Stuck in this for the past 10 days.

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eltn=30;
%%(b)Element Connectivity Table
count = 0 ;
conn = zeros([],3) ;
for i=1:30
for j=1:27
count = count+1 ;
conn(count,:) =[j,j+1,j+2]
end
end
%Here the Code for Assembling (OR) Global Mass Matrix
%x(i,j)=Kte_matrix(i,j); %DOUBT +=
for i=1:27
for j=1:27
MG_matrix(conn(eltn,i) - 1,conn(eltn,j) - 1)= Mte_matrix(i,j); (ERROR HERE)
end
end
How to convert conn matrix in this range??
Attempted to access conn(30,4); index out of bounds because size(conn)=[810,3].
Error in practisee2 (line 558) MG_matrix(conn(eltn,i) - 1,conn(eltn,j) - 1)= Mte_matrix(i,j);
  11 Comments
Virajan Verma
Virajan Verma on 13 Nov 2018
That conn matrix is showing index out of bounds error as it has only 3 columns and for i>3, it has no elements to show. That is why i changed the initialization.

Answers (1)

KSSV
KSSV on 12 Nov 2018
Check the function assemble in the link. This will help you.
  8 Comments
Stephen23
Stephen23 on 13 Nov 2018
Edited: Stephen23 on 13 Nov 2018
"The value of conn(eltn,j) for j=1 should be 59. How can it be zero??"
Who said that j is equal to one when that error occurs? I don't see anything in your code that means that j equals one when that error occurs. Try looking at the value of j after the error has occured, and you might just learn something about your code.

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