How can I match a string in a cell array and then pull out data from the row with the match?
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Hello,
I have been struggling to solve this problem on my own after combing the internet for solutions. Here is my code below.
A = {'Red123' 'Bob' '08/11/2018' 'Blah'; 'Red456' 'Jim' '11/08/2018' 'Meh'; 'Blue123' 'Bean' '02/11/2018' 'MoreMeh';...
'Blue456' 'Dale' '05/05/2005' 'Nope'};
IDTag = 'Blue123';
check = strcmp(A,IDTag);
check returns a 4x4 logical array with a 1 where I would expect it. What I'd like to figure out how to do is to then take the data after the match in the row (in this case it would be A(3)). So I'd like to have my script find the match and then assign A(3,2) and A(3,3) to variables to be passed off elsewhere. How can I do this dynamically and autonomously so when I need to pass in variables to check this list, I can quickly match and pull out data?
To reiterate, I want to match on Blue123, and if it is a match, I want to assign 'Bean' and '02/11/2018' to two different variables for later use. If I later want to match a different IDTag, I want it to do the same thing.
Thank you!
Accepted Answer
More Answers (1)
For now i am assuming the ID is always in the first column. You could have the logical matrix repeat itself and then use that as an index:
% your code
A = {'Red123' 'Bob' '08/11/2018' 'Blah'; 'Red456' 'Jim' '11/08/2018' 'Meh'; 'Blue123' 'Bean' '02/11/2018' 'MoreMeh';...
'Blue456' 'Dale' '05/05/2005' 'Nope'};
IDTag = 'Blue123';
check = strcmp(A,IDTag);
% change the check matrix to have the entire row the same as the first row
check = repmat(check(:,1), 1, size(check,2));
correspondingData = A(check);
name = correspondingData{2};
date = correspondingData{3};
alternatively you can also do:
index = find(check(:,1)==1);
correspondingData = A(index,:);
name = correspondingData{2};
date = correspondingData{3};
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