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How can I create a gradient of 255 line plots?

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I am plotting many lines on a single plot but too many to manually give each line a specific color. I need to create a gradient of these lines (each line representing a different time point) to show that the lines gradually shift down. I figured out how to create a gray gradient but can't figure out how to create a color gradient. This is the command written for the gray gradient and attached an image of what it looks like. % sheet=1 DataZ=csvread(trimname,sheet) % plotsize=size(DataZ,2) Frequency=DataZ(:,1) %hours Zimpedance=DataZ(:,2:plotsize) LogZ=log10(Zimpedance) contour(LogZ) mesh(LogZ) % get(gca,'ColorOrder') N = plotsize; C = repmat(linspace(1,0.1,N).',1,3); axes('ColorOrder',C,'NextPlot','replacechildren') plot(log10(Frequency),LogZ) title('60C Harr/DI 0V PE') xlabel('Log Frequency (Hz)') ylabel('Log Z (Ohm)')

Answers (2)

Akira Agata
Akira Agata on 7 Nov 2018
I think the solution would be like this. In this example, like color changes as the y-intercept of the like decrease.
% Gradually shifting lines data
% "plot(Frequency,Data(:,k))" shows k-th line
yIntercept = 10*exp(-0.05*(1:100));
Data = repmat(linspace(2,1)',1,100);
Data = Data + yIntercept;
Frequency = linspace(1,2)';
% Set color vector
c = parula(100);
% Visualize the result
figure
hold on
for kk = 1:100
plot(Frequency,Data(:,kk),'Color',c(kk,:))
end
box on
  3 Comments
Akira Agata
Akira Agata on 9 Nov 2018
Please replace 'Set color vector' section in the above script as follows. In this case, the total number of line is assumed to 100.
% Set color vector
cStart = uisetcolor([1 0.8 0.8],'Select a start color');
cEnd = uisetcolor([0.8 0.0 0],'Select an end color');
c = interp1([1;100],[cStart;cEnd],(1:100)');
AnaelG
AnaelG on 4 Mar 2020
Now is there an elegant way to do that (without a for loop) ? :D

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Simon Dengler
Simon Dengler on 29 Nov 2022
I'm using
colororder([jet(44)])
for similar functionality

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