Why does:
diffpressure = gradient(pressure)./gradient(density);
and
diffpressure = diff(pressure)./diff(density);
give drastically different results? The derivative using each method are completely different. See attached figure

 Accepted Answer

Matt J
Matt J on 5 Nov 2018
Edited: Matt J on 5 Nov 2018

2 votes

gradient uses central differences while diff(x) uses right-hand differences x(i+1)-x(i).

12 Comments

Benjamin
Benjamin on 5 Nov 2018
Look at my attached figure, should they really be that different?
Matt J
Matt J on 5 Nov 2018
I don't see why not, but on the other hand the picture isn't all that informative. You should provide the input data in a .mat file.
Benjamin
Benjamin on 5 Nov 2018
Check file now. It shows the original function, and the derivative using diff and derivative using grad. Surely, the derivative is not that sensitive to the method. I have hundreds of points on the curve.
Matt J
Matt J on 5 Nov 2018
I see no change in the attachment.
Benjamin
Benjamin on 5 Nov 2018
Sorry, check now
Matt J
Matt J on 5 Nov 2018
Edited: Matt J on 5 Nov 2018
You have only plotted one of the original functions. We cannot tell if this is density or pressure and without both we also cannot gain any insight into the ratio of their gradients.
Once again, the most helpful thing would be to attach your numeric data in a .mat file.
Matt J
Matt J on 5 Nov 2018
Edited: Matt J on 5 Nov 2018
My preliminary guess would be that the gradient of density is tending toward zero, where the ratio calculation gradient(pressure)./gradient(density) becomes numerically unstable.
Benjamin
Benjamin on 5 Nov 2018
The y-axis is pressure, x-axis is density. Ok, I'll try and attach, but quick question: If I have x values and yvalues, how would I differentiate y wrt to x? do I do diff(y)/diff(x) or just do diff(y) and plot it as plot(x,diff(y))
Benjamin
Benjamin on 5 Nov 2018
Perhaps the better question is, if I have numerical X and Y data, what way should I differentiate y with respect to x?
Benjamin
Benjamin on 5 Nov 2018
Do you think diff(y) / diff(x) is the way to go here?
Yes!
Matt J
Matt J on 5 Nov 2018
Edited: Matt J on 5 Nov 2018
If the X-data are not equi-spaced, use diff().

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