Check an array of values if within an upper and lower limit

I am trying to do the same thing as the following example but checking an array of numbers and not just x. However it is not working. can someone help?

x = 10;
minVal = 2;
maxVal = 6;

if (x >= minVal) && (x <= maxVal)
    disp('Value within specified range.')
elseif (x > maxVal)
    disp('Value exceeds maximum value.')
else
    disp('Value is below minimum value.')
end

Answer 1

[Dennis]

If you want to operate on arrays you could do it like this:

x = 1:10;
minVal = 2;
maxVal = 6;
x(x(x<=maxVal)>=minVal)
disp('Values within specified range.')

[Ayman Fathy]

I basically have an array of 2 columns, first column contains numbers from 0 to 3000 and the second column contains temperature data. I want to store the temperature data in the 3rd column in the same array if the corresponding number in the first column lies between 1000 and 2000 otherwise Nan, I tried your code but it gives me a 3rd column that is the same as the 2nd column

[Dennis]

x = [randi(10,19,1),randi(100,19,1)];
minVal = 2;
maxVal = 6;
x(:,3)=NaN;
idx=find(x(:,1)>=minVal&x(:,1)<=maxVal);
x(idx,3)=x(idx,2)

[Ayman Fathy]

Thanks a lot. It worked!!

Answer 2

[KSSV]

minVal = 2;
maxVal = 6;
if any(x >= minVal) && any(x <= maxVal)
    disp('Value within specified range.')
elseif any(x > maxVal)
    disp('Value exceeds maximum value.')
else
    disp('Value is below minimum value.')
end

[Ayman Fathy]

I basically have an array of 2 columns, first column contains numbers from 0 to 3000 and the second column contains temperature data. I want to store the temperature data in the 3rd column in the same array if the corresponding number in the first column lies between 1000 and 2000 otherwise Nan, I tried your code but it gives me a 3rd column that is the same as the 2nd column

[Ayman Fathy]

Lowerlimit = 1000; Upperlimit = 2000;

if any(s(:,1) >= Lowerlimit) && any(s(:,1) <= Upperlimit) s(:,3) = s(:,2); else s(:,3) = NaN; end

%Itried this code but didnt work

[Ayman Fathy]

this was my code previously and again didnt work:

% for x = size(s, 1) % % if (s(x, 1) >=Lowerlimit) (s(x,1) <= Upperlimit) % s(x, 3) = s(x, 2); % else % s(x, 2) = NaN; % end % end