how can I convert a geospacial sst map from 4km to 6 km or vice versa

[X,Y] = meshgrid(lon1:lon2, lat1:lat2); V = sst; [Xq,Yq] = meshgrid(lon:6:lat); Vq = interp2(X,Y,V,Xq,Yq)

Answer 1

[ANKUR KUMAR]

clc
clear
lon=[65:.04:70];
lat=[0:0.04:5]; %on 4km resolution
sst_4km=randi(27,126,126);
lon1=[65:.06:70];
lat1=[0:0.06:5]; %on 6 km resolution
[lon1_mesh,lat1_mesh]=meshgrid(lon1,lat1);
for ii=1:size(lon1_mesh,1)
    sst_6km=interp2(lon,lat,sst_4km,lon1_mesh(ii,:),lat1_mesh(ii,:));
end

[Hana Mirza]

This answer didn't work as my SST is not a randi function. I'm not sure also how the array can be incorporated since the data set have are over 15 years.

[ANKUR KUMAR]

Since you haven't attached you file, that's why I have taken random numbers to explain. In place of sst_4km, load you sst from file and do further calculations.

[Tanziha Mahjabin]

Hi, I am having some error saying :

{Error using .'

Transpose on ND array is not defined. Use PERMUTE instead.

Error in interp2 (line 122)

V = V.'; }

My code is followed:

time2=ncread(fileIn,'time');

time2=ncread(fileIn,'time')./86400+datenum(1981,01,01);

SST_lon=ncread(fileIn,'lon');

SST_lat=ncread(fileIn,'lat');

SST=ncread(fileIn,'sea_surface_temperature');

SST=SST-273.15;

id1=(SST_lat>-39.9&SST_lat<-36.2);

id2=(SST_lon>137.1&SST_lon<141.9);

lat1=SST_lat(id1);

lon1=SST_lon(id2);

[lon1_mesh,lat1_mesh]=meshgrid(lon1,lat1);

for ii=1:size(lon1,1)

SSTg=interp2(SST_lon,SST_lat,SST,lon1_mesh(ii,:),lat1_mesh(ii,:));

end