Intersection between line and function
11 views (last 30 days)
Show older comments
hello i draw graphics on matlab based on data found in tables, and what i'm trying to do is project a Y value and find its equivalent X, i give you the code used to create the projection Y, as well as the graph
xlim([0,50])
YV = [min(X1)-0.1:0.01:max(X1)+0.1];
XVmax = zeros(1,numel(YV));
j = [1:numel(YV)];
XVmax(j)= max(Y2_max);
plot(YV,XVmax,'--m')
0 Comments
Answers (1)
jonas
on 3 Aug 2018
Edited: jonas
on 3 Aug 2018
%%Some data
x=0:.9:20;
y=x.^2
%%Set threshold
t=200;
yt=[t t]
xt=[min(x),max(x)];
P=InterX([xt;yt],[x;y])
h=plot(x,y,'+-k',...
xt,yt,'r',...
P(1),P(2),'bo')
set(h(3),'markerfacecolor',[1 0 0])
Note that the resolution of the x-range is quite poor, yet the intercep is accurate.
0 Comments
See Also
Categories
Find more on Graphics Performance in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!