How to take first element from the cell?

Dear all,

I have a cell

d={[3,80,32,13]  [3,80,17]  [3,45,18]  [3,45,20]  [3,80,32]  [3,45]  [3,80,47]  [3,45,93,62]  [3,80]  [3,45,93]}

Also I have vector c= [80 45];

The question is : How to take the first element that locate it after vector c numbers ?

The expected result is =

{[32] [17] [18] [20] [32] [] [47] [93] [] [93]}

Also I would like to get other elements that locate it after the first element in another cell, for example:

 x = {[13] [] [] [] [] [] [62] [] []}

please help>>>>

Answer 1

[Stephen23]

Something like this (untested, but should get you started):

N = numel(d);
R = cell(1,N);
X = cell(1,N);
for k = 1:N
    idx = ismember(d{k},[80,45]);
    idx = [false,idx(1:end-1)];
    if any(idx)
        R{k} = d{k}(find(idx,1,'first'));
    end
    idx = [false,idx(1:end-1)];
    if any(idx)
        X{k} = d{k}(find(idx,1,'first'));
    end
end

[laith Farhan]

Thanks a lot Stephen , that really help

[Stephen23]

@laith Farhan: I hope that it helped. Remember to accept the answer that helped you most: accepting answers is the easiest way to show your appreciation to the volunteers who help you on this forum.