Converting a 3D matrix into a 2D in the correct order.

Hi guys, so i have a index matrix of 1x8x50 (i know this is almost a vector). exemple:

T(:,:,48) = 37.3795 32.7215 31.9475 35.0683 35.8266 61.2570 45.0210 44.3608

T(:,:,49) = 38.7236 33.9132 33.1193 36.3396 37.1225 63.2087 46.5356 45.9089

And i Want to put it all in a 2D matrix with the index of (50;8). But when do reshape(T[size(T,3),size(T,2)]), it organizes the matrix by column. What i would like is that each 3D matriz would be a row of my 2D matrix. Like T(:,:,1) would be the first line of the 2D matrix and so on.

Thank you!!

[KSSV]

Read about squeeze

Answer 1

[Andrei Bobrov]

permute(T,[3,2,1])

[Stephen23]

+1 permute is the correct way to do this.

[Andrei Bobrov]

Thank you Stephen!

Answer 2

[Sayyed Ahmad]

for i=1:8
  for j=1:50
    a(1,i,j)=i*10000+j;
  end
end
b=a;
b=reshape(b,8,50);
b=b';