how to crop the region image only and eliminate the light

i have some problem,, i caputured imaged from my camera

picture 1 : <http://tinypic.com/view.php?pic=k4yyyd&s=6>

picture 2 :http://tinypic.com/view.php?pic=zumsjm&s=6

I need coding to solve the problem,,,, ceramic picture above there is still a light on it, how do I get rid of the light (reduce light) ???? and also how to crop that images just crop the region of ceramic tiles? (i ever used coding imcrop , but imcrop just crop into rectanguler not specify on edge)

[Ryan]

Do you wish to crop the tiles automatically or via the user?

[KURNIAWAN]

just crop the region first? before i wanna process the picture into m-file, i wanna crop 1st and loss the light,,

Answer 1

[Image Analyst]

Find the tile, like I showed you before. Then use the any() function and find() function to find the top and bottom rows of the binary image, and the left and right edge of the binary image. Then construct your rectangle [x y width height] and pass that in to imcrop. About 7 lines of code (minimum). Something like

hProfile = any(binaryImage, 1);
col1 = find(hProfile , 1, 'first');
col2 = find(hProfile , 1, 'last');
vProfile = any(binaryImage, 2);
row1 = find(vProfile , 1, 'first');
row2 = find(vProfile , 1, 'last');
imcrop(.....

Give it a try.

[KURNIAWAN]

but you showed before,, not crop yet,, i confused,,, i use imcrop but the picture become rectanguler not specify each edge...

i need simply coding 1st ,, and croping then loss light,,

pls teach me

[Image Analyst]

Before I showed you how to get the binary image. That code is the starting point for this code. You add this code onto that code. I gave you nearly everything except the imcrop line. It's something like this:

croppedImage = imcrop(rgbImage, [col1, row1, col2-col1+1, row2-row1+1]);

[Walter Roberson]

It is only possible to crop rectangular regions, because MATLAB can only store rectangular arrays.

You can set areas to have a value such as black (zeros).

[KURNIAWAN]

ohh,, matlab cant crop specify edge?? now i see,,, thanks image analyst,, n Walter Roberson... i will ask later if i confuse ... i hope u can tech me