the question is attached I have to answer, but I'm having problems.
I tried writing like this
fun = @(t,w)exp((-1i).*w.*t);
q=integral(@(t)fun(t,w),-1,1);
int() is recommended, but can it be written like above?

 Accepted Answer

You are close to solving it. You need to express ‘q’ as an anonymous function of ‘w’, then evaluate that function over the interval (-10,10):
fun = @(t,w)exp(-1i.*w.*t);
q = @(w) integral(@(t)fun(t,w),-1,1, 'ArrayValued',true);
wv = linspace(-10, 10);
figure(1)
plot(wv, real(q(wv)), '-b', wv, imag(q(wv)), '-r')
grid
So yes, you can use integral to evaluate the Fourier transform of your function. (It never occurred to me to do this, so I learned something.)

2 Comments

doyoun Kim
doyoun Kim on 21 May 2018
Edited: doyoun Kim on 21 May 2018
Thx a lot
As always, my pleasure.

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