How to generate several matrix by varying one value?

I'm using that code below, and I want to get 6 matrix, according to the value of "i". the problem is that I get only i=15. so just one value of "i", and then one results.

How can I force it to use all the values from i=10 till i=15

for i=10:15;
A= [i   0   0  30 ; 70  30   0   0 ; 30  70   0   0 ; 30   0  70   0];

B= [1; 2; 3; 4];
C = inv(A);
D= A\B;
end
E=bsxfun(@times,i,B)
i

Thank you

Answer 1

[Stephen23]

A = [0,0,0,30;70,30,0,0;30,70,0,0;30,0,70,0];
B = [1;2;3;4];
vec = 10:15;
out = cell(size(vec));
for k = 1:numel(vec)
    A(1) = vec(k);
    out{k} = A\B;
end
E = bsxfun(@times,vec,B)

Giving:

>> out{:}
ans =
   0.012500
   0.037500
   0.051786
   0.029167
ans =
   0.012500
   0.037500
   0.051786
   0.028750
ans =
   0.012500
   0.037500
   0.051786
   0.028333
ans =
   0.012500
   0.037500
   0.051786
   0.027917
ans =
   0.012500
   0.037500
   0.051786
   0.027500
ans =
   0.012500
   0.037500
   0.051786
   0.027083

See also: https://www.mathworks.com/help/matlab/matlab_prog/access-data-in-a-cell-array.html

[Redouane Ch]

Thank you for your help, but still whene I use

Sol=bsxfun(@times, vec, out{k});

we get only an operation with the last cell, from out{k}, not all of them. How can we operat in all of them?

[Stephen23]

"How can we operat in all of them?"

Move that operation inside the loop. Having the operation inside the loop would means that on each iteration you could perform that calculation. That is what loops do.

[Redouane Ch]

with

for k = 1:numel(vec)
    A(1) = vec(k);
    out{k} = A\B;
    Sol=bsxfun(@times, vec, out{k});
end

I get

Sol =

      0.1250    0.1375    0.1500    0.1625    0.1750    0.1875
      0.3750    0.4125    0.4500    0.4875    0.5250    0.5625
      0.5179    0.5696    0.6214    0.6732    0.7250    0.7768
      0.2708    0.2979    0.3250    0.3521    0.3792    0.4062

and that's using one cell only

[Stephen23]

@Redouane Ch: have a look at the code in my answer. Do you see how I define out before the loop, and within the loop allocate values to it using indexing? That is what you need to do too.

[Redouane Ch]

Thank you, it works with:

count=1;
for k = 1:numel(vec)
    A(1) = vec(k); 
    out{k} = A\B;
    Sola(count,:)=out{k};
    count=count+1;
end
Solb=bsxfun(@times, vec', Sola);

Answer 2

[Andrei Bobrov]

ii = 10:15;
A= [0    0   0  30 ; 
    70  30   0   0 ; 
    30  70   0   0 ; 
    30   0  70   0];

n = numel(ii);
A = repmat(A,1,1,numel(ii));
A(1,1,:) = ii;
s = size(A);
B= [1; 2; 3; 4];

D = zeros(numel(B),n);
C = zeros(s);
es = eye(s);
for jj = 1:n
    D(:,jj) = A(:,:,jj)\B;
    C(:,:,jj) = A(:,:,jj)\es;
end

E = bsxfun(@times,ii(:),B);

[Redouane Ch]

Thank you for your help

[Redouane Ch]

Actually, I couldn't use your code, seems there's a problem in

es = eye(s);