Find length of a structure element and remove them according to length?

If I have a structure "output" with a field "output.I".

How can I check the lengths of all the output(1:end).I in one go and then remove the those rows from the structure that I do not require.

For example

output(1).I has a length of 100X1
output(2).I has a length of 200X1
output(3).I has a length of 100X1

I want to remove output(2).I = [] and my final structure to only have output(1).I and output(3).I

Please advise.

[Rik]

Do you want to remove the structure element, or just empty out the field? The latter can be easily solved with a loop (and there may be several methods to do it faster), while the first is quite tricky (and will cause your elements to be renumbered).

[Arif Ahmed]

I want to remove the element. The indexing will be an issue and so I was thinking maybe there is an easy way to do it.

Answer 1

[Jos (10584)]

L = arrayfun(@(k) numel(output(k).I), 1:numel(output))
output(L > 100) = [] ; % remove those elements of the structure array

Answer 2

[Stephen23]

Simpler:

len = arrayfun(@(s)numel(s.I),output);
output(len>100) = []

Or simplest:

len = cellfun('length',{output.I});
output(len>100) = []

Answer 3

[Arif Ahmed]

If I could I would accept all answers. Amazing guys! Thanks for the help.

Stephen Cobeldick, your code is really simple! Appreciate it.