conditional adding of elements to an array

i have the following array: [2 2 4 6 7 16 20 29 48 81 130 163 235 308 414 496 535 521 509 465 355 275 198 120 72 31 16 8 4 2]

what i want to do is if the element of the array is greater than 50, then i replace the element by the the 50 then by the remainder so for example after converting the 10th element the array becomes [2 2 4 6 7 16 20 29 48 50 31 130 163 235 308 414 496 535 521 509 465 355 275 198 120 72 31 16 8 4 2]

how wcan this be done for any array ?

[James Tursa]

Do this for only the first occurrence, or for all elements? What if the remainder is still greater than 50? Could an element expand into more than two elements?

[Ahmad Beydoun]

yes the element should be divided till the floor of the division is zero and for all occurrence

Answer 1

[James Tursa]

A = your data vector
n = whatever (e.g., 50)
result = cell2mat(arrayfun(@(x)[repmat(n,1,floor(x/n)),rem(x,n)],A,'uni',false));

[Ahmad Beydoun]

thank you !!! you have no idea how much i appreciate your help

[James Tursa]

You should use Rik's answer since he covers the case for exact multiples!

Answer 2

[Rik]

Not the most beautiful code I've ever written, but this should do what you want. I tested it as well with [0 50].

a=[2  2  4  6  7  16  20  29  48  81  130  163  235  308  414  496  535  521  509 465  355  275  198  120  72  31  16  8  4  2];
a=num2cell(a);
fun=@(x) [repmat(50,1,floor(x/50)) repmat(mod(x,50),1,mod(x,50)~=0)];
result=cellfun(fun,a,'UniformOutput',false);
result=cell2mat(result);

[Ahmad Beydoun]

thank you rick !! much appreciated !!